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Old Perl 5 Man Pages
(Annotated for Nikolai Bezroukov's Perl course students for education purposes only)
perldsc - Perl Data Structures Cookbook
The single feature most sorely lacking in the Perl programming language prior to
its 5.0 release was complex data structures. Even without direct language
support, some valiant programmers did manage to emulate them, but it was hard
work and not for the faint of heart. You could occasionally get away with the
$m{$LoL,$b}
notation borrowed from awk in which the keys are actually more like a
single concatenated string ``$LoL$b'',
but traversal and sorting were difficult. More desperate programmers even hacked
Perl's internal symbol table directly, a strategy that proved hard to develop
and maintain--to put it mildly.
The 5.0 release of Perl let us have complex data structures. You may now
write something like this and all of a sudden, you'd have a array with three
dimensions!
for $x (1 .. 10) { for $y (1 .. 10) { for $z (1 .. 10) { $LoL[$x][$y][$z] = $x
** $y + $z; } } }
Alas, however simple this may appear, underneath it's a much more elaborate
construct than meets the eye!
How do you print it out? Why can't you just say print @LoL?
How do you sort it? How can you pass it to a function or get one of these back
from a function? Is is an object? Can you save it to disk to read back later?
How do you access whole rows or columns of that matrix? Do all the values have
to be numeric?
As you see, it's quite easy to become confused. While some small portion of
the blame for this can be attributed to the reference-based implementation, it's
really more due to a lack of existing documentation with examples designed for
the beginner.
This document is meant to be a detailed but understandable treatment of the
many different sorts of data structures you might want to develop. It should
also serve as a cookbook of examples. That way, when you need to create one of
these complex data structures, you can just pinch, pilfer, or purloin a drop-in
example from here.
Let's look at each of these possible constructs in detail. There are separate
documents on each of the following:
- * arrays of arrays
-
- * hashes of arrays
-
- * arrays of hashes
-
- * hashes of hashes
-
- * more elaborate constructs
-
- * recursive and self-referential data structures
-
- * objects
-
But for now, let's look at some of the general issues common to allof these
types of data structures.
The most important thing to understand about all data structures in Perl --
including multidimensional arrays--is that even though they might appear
otherwise, Perl @ARRAYs and %HASHes
are all internally one-dimensional. They can only hold scalar values (meaning a
string, number, or a reference). They cannot directly contain other arrays or
hashes, but instead contain references to other arrays or hashes.
You can't use a reference to a array or hash in quite the same way that you
would a real array or hash. For C or C++ programmers unused to distinguishing
between arrays and pointers to the same, this can be confusing. If so, just
think of it as the difference between a structure and a pointer to a structure.
You can (and should) read more about references in the perlref(1) man page.
Briefly, references are rather like pointers that know what they point to.
(Objects are also a kind of reference, but we won't be needing them right
away--if ever.) This means that when you have something which looks to you like
an access to a two-or-more-dimensional array and/or hash, what's really going on
is that the base type is merely a one-dimensional entity that contains
references to the next level. It's just that you can use it as though
it were a two-dimensional one. This is actually the way almost all C
multidimensional arrays work as well.
$list[7][12] # array of arrays $list[7]{string} # array of hashes
$hash{string}[7] # hash of arrays $hash{string}{'another string'} # hash of
hashes
Now, because the top level only contains references, if you try to print out
your array in with a simple print() function, you'll get something that
doesn't look very nice, like this:
@LoL = ( [2, 3], [4, 5, 7], [0] ); print $LoL[1][2]; 7 print @LoL;
ARRAY(0x83c38)ARRAY(0x8b194)ARRAY(0x8b1d0)
That's because Perl doesn't (ever) implicitly dereference your variables. If
you want to get at the thing a reference is referring to, then you have to do
this yourself using either prefix typing indicators, like ${$blah},
@{$blah}, @{$blah[$i]},
or else postfix pointer arrows, like $a->[3],
$h->{fred},
or even $ob->method()->[3].
The two most common mistakes made in constructing something like an array of
arrays is either accidentally counting the number of elements or else taking a
reference to the same memory location repeatedly. Here's the case where you just
get the count instead of a nested array:
for $i (1..10) { @list = somefunc($i); $LoL[$i] = @list; # WRONG! }
That's just the simple case of assigning a list to a scalar and getting its
element count. If that's what you really and truly want, then you might do well
to consider being a tad more explicit about it, like this:
for $i (1..10) { @list = somefunc($i); $counts[$i] = scalar @list; }
Here's the case of taking a reference to the same memory location again and
again:
for $i (1..10) { @list = somefunc($i); $LoL[$i] = \@list; # WRONG! }
So, just what's the big problem with that? It looks right, doesn't it? After
all, I just told you that you need an array of references, so by golly, you've
made me one!
Unfortunately, while this is true, it's still broken. All the references in
@LoL
refer to the very same place, and they will therefore all hold whatever
was last in @list! It's similar to the problem demonstrated in
the following C program:
#include
main() { struct passwd *getpwnam(), *rp, *dp; rp = getpwnam("root");
dp = getpwnam("daemon"); printf("daemon name is %s\nroot name is
%s\n", dp->pw_name, rp->pw_name); }
Which will print
daemon name is daemon root name is daemon
The problem is that both rp and dp are pointers to
the same location in memory! In C, you'd have to remember to malloc()
yourself some new memory. In Perl, you'll want to use the array constructor []
or the hash constructor {} instead. Here's the right way to do the
preceding broken code fragments:
for $i (1..10) { @list = somefunc($i); $LoL[$i] = [ @list ]; }
The square brackets make a reference to a new array with a copy of
what's in @list at the time of the assignment. This is what you
want.
Note that this will produce something similar, but it's much harder to read:
for $i (1..10) { @list = 0 .. $i; @{$LoL[$i]} = @list; }
Is it the same? Well, maybe so--and maybe not. The subtle difference is that
when you assign something in square brackets, you know for sure it's always a
brand new reference with a new copy of the data. Something else could
be going on in this new case with the @{$LoL[$i]}}
dereference on the left-hand-side of the assignment. It all depends on whether
$LoL[$i]
had been undefined to start with, or whether it already contained a reference.
If you had already populated @LoL with references, as in
$LoL[3] = \@another_list;
Then the assignment with the indirection on the left-hand-side would use the
existing reference that was already there:
@{$LoL[3]} = @list;
Of course, this would have the ``interesting'' effect of clobbering
@another_list.
(Have you ever noticed how when a programmer says something is ``interesting'',
that rather than meaning ``intriguing'', they're disturbingly more apt to mean
that it's ``annoying'', ``difficult'', or both? :-)
So just remember to always use the array or hash constructors with []
or {}, and you'll be fine, although it's not always optimally
efficient.
Surprisingly, the following dangerous-looking construct will actually work
out fine:
for $i (1..10) { my @list = somefunc($i); $LoL[$i] = \@list; }
That's because my() is more of a run-time statement than it is a
compile-time declaration per se. This means that the my()
variable is remade afresh each time through the loop. So even though it looks
as though you stored the same variable reference each time, you actually did
not! This is a subtle distinction that can produce more efficient code at the
risk of misleading all but the most experienced of programmers. So I usually
advise against teaching it to beginners. In fact, except for passing arguments
to functions, I seldom like to see the gimme-a-reference operator (backslash)
used much at all in code. Instead, I advise beginners that they (and most of the
rest of us) should try to use the much more easily understood constructors []
and {} instead of relying upon lexical (or dynamic) scoping and
hidden reference-counting to do the right thing behind the scenes.
In summary:
$LoL[$i] = [ @list ]; # usually best $LoL[$i] = \@list; # perilous; just how
my() was that list? @{ $LoL[$i] } = @list; # way too tricky for most programmers
Speaking of things like @{$LoL[$i]},
the following are actually the same thing:
$listref->[2][2] # clear $$listref[2][2] # confusing
That's because Perl's precedence rules on its five prefix dereferencers
(which look like someone swearing: $ @ * % &) make them bind
more tightly than the postfix subscripting brackets or braces! This will no
doubt come as a great shock to the C or C++ programmer, who is quite accustomed
to using *a[i] to mean what's pointed to by the i'th
element of a. That is, they first take the subscript, and only then
dereference the thing at that subscript. That's fine in C, but this isn't C.
The seemingly equivalent construct in Perl, $$listref[$i]
first does the deref of $listref, making it take $listref
as a reference to an array, and then dereference that, and finally tell you the i'th
value of the array pointed to by $LoL. If you wanted the C
notion, you'd have to write ${$LoL[$i]}
to force the $LoL[$i] to get
evaluated first before the leading $ dereferencer.
WHY YOU SHOULD ALWAYS use strict
If this is starting to sound scarier than it's worth, relax. Perl has some
features to help you avoid its most common pitfalls. The best way to avoid
getting confused is to start every program like this:
#!/usr/bin/perl -w use strict;
This way, you'll be forced to declare all your variables with my()
and also disallow accidental ``symbolic dereferencing''. Therefore if you'd done
this:
my $listref = [ [ "fred", "barney", "pebbles",
"bambam", "dino", ], [ "homer", "bart",
"marge", "maggie", ], [ "george",
"jane", "alroy", "judy", ], ]; print
$listref[2][2];
The compiler would immediately flag that as an error at compile time,
because you were accidentally accessing @listref,
an undeclared variable, and it would thereby remind you to instead write:
print $listref->[2][2]
Before 5.002, the standard Perl debugger didn't do a very nice job of printing
out complex data structures. With version 5.002 or above, the debugger includes
several new features, including command line editing as well as the x
command to dump out complex data structures. For example, given the assignment
to $LoL above, here's the debugger output:
DB<1> X $LoL $LoL = ARRAY(0x13b5a0) 0 ARRAY(0x1f0a24) 0 'fred' 1 'barney'
2 'pebbles' 3 'bambam' 4 'dino' 1 ARRAY(0x13b558) 0 'homer' 1 'bart' 2 'marge' 3
'maggie' 2 ARRAY(0x13b540) 0 'george' 1 'jane' 2 'alroy' 3 'judy'
There's also a lower-case x command which is nearly the
same.
Presented with little comment (these will get their own man pages someday) here
are short code examples illustrating access of various types of data structures.
@LoL = ( [ "fred", "barney" ], [ "george",
"jane", "elroy" ], [ "homer", "marge",
"bart" ], );
# reading from file while ( <> ) { push @LoL, [ split ]; } # calling a
function for $i ( 1 .. 10 ) { $LoL[$i] = [ somefunc($i) ]; } # using temp vars
for $i ( 1 .. 10 ) { @tmp = somefunc($i); $LoL[$i] = [ @tmp ]; } # add to an
existing row push @{ $LoL[0] }, "wilma", "betty";
# one element $LoL[0][0] = "Fred"; # another element $LoL[1][1] =~
s/(\w)/\u$1/; # print the whole thing with refs for $aref ( @LoL ) { print
"\t [ @$aref ],\n"; } # print the whole thing with indices for $i ( 0
.. $#LoL ) { print "\t [ @{$LoL[$i]} ],\n"; } # print the whole thing
one at a time for $i ( 0 .. $#LoL ) { for $j ( 0 .. $#{$LoL[$i]} ) { print
"elt $i $j is $LoL[$i][$j]\n"; } }
%HoL = ( "flintstones" => [ "fred", "barney" ],
"jetsons" => [ "george", "jane",
"elroy" ], "simpsons" => [ "homer",
"marge", "bart" ], );
# reading from file # flintstones: fred barney wilma dino while ( <> ) {
next unless s/^(.*?):\s*//; $HoL{$1} = [ split ]; } # reading from file; more
temps # flintstones: fred barney wilma dino while ( $line = <> ) { ($who,
$rest) = split /:\s*/, $line, 2; @fields = split ' ', $rest; $HoL{$who} = [
@fields ]; } # calling a function that returns a list for $group (
"simpsons", "jetsons", "flintstones" ) {
$HoL{$group} = [ get_family($group) ]; } # likewise, but using temps for $group
( "simpsons", "jetsons", "flintstones" ) {
@members = get_family($group); $HoL{$group} = [ @members ]; } # append new
members to an existing family push @{ $HoL{"flintstones"} },
"wilma", "betty";
# one element $HoL{flintstones}[0] = "Fred"; # another element
$HoL{simpsons}[1] =~ s/(\w)/\u$1/; # print the whole thing foreach $family (
keys %HoL ) { print "$family: @{ $HoL{$family} }\n" } # print the
whole thing with indices foreach $family ( keys %HoL ) { print "family:
"; foreach $i ( 0 .. $#{ $HoL{$family} ) { print " $i =
$HoL{$family}[$i]"; } print "\n"; } # print the whole thing
sorted by number of members foreach $family ( sort { @{$HoL{$b}} <=>
@{$HoL{$b}} } keys %HoL ) { print "$family: @{ $HoL{$family} }\n" } #
print the whole thing sorted by number of members and name foreach $family (
sort { @{$HoL{$b}} <=> @{$HoL{$a}} } keys %HoL ) { print "$family:
", join(", ", sort @{ $HoL{$family}), "\n"; }
@LoH = ( { Lead => "fred", Friend => "barney", }, {
Lead => "george", Wife => "jane", Son =>
"elroy", }, { Lead => "homer", Wife =>
"marge", Son => "bart", } );
# reading from file # format: LEAD=fred FRIEND=barney while ( <> ) { $rec
= {}; for $field ( split ) { ($key, $value) = split /=/, $field; $rec->{$key}
= $value; } push @LoH, $rec; } # reading from file # format: LEAD=fred
FRIEND=barney # no temp while ( <> ) { push @LoH, { split /[\s+=]/ }; } #
calling a function that returns a key,value list, like #
"lead","fred","daughter","pebbles" while
( %fields = getnextpairset() ) { push @LoH, { %fields }; } # likewise, but using
no temp vars while (<>) { push @LoH, { parsepairs($_) }; } # add key/value
to an element $LoH[0]{pet} = "dino"; $LoH[2]{pet} = "santa's
little helper";
# one element $LoH[0]{lead} = "fred"; # another element $LoH[1]{lead}
=~ s/(\w)/\u$1/; # print the whole thing with refs for $href ( @LoH ) { print
"{ "; for $role ( keys %$href ) { print "$role=$href->{$role}
"; } print "}\n"; } # print the whole thing with indices for $i (
0 .. $#LoH ) { print "$i is { "; for $role ( keys %{ $LoH[$i] } ) {
print "$role=$LoH[$i]{$role} "; } print "}\n"; } # print the
whole thing one at a time for $i ( 0 .. $#LoH ) { for $role ( keys %{ $LoH[$i] }
) { print "elt $i $role is $LoH[$i]{$role}\n"; } }
%HoH = ( "flintstones" => { "lead" =>
"fred", "pal" => "barney", },
"jetsons" => { "lead" => "george",
"wife" => "jane", "his boy" =>
"elroy", }, "simpsons" => { "lead" =>
"homer", "wife" => "marge", "kid"
=> "bart", }, );
# reading from file # flintstones: lead=fred pal=barney wife=wilma pet=dino
while ( <> ) { next unless s/^(.*?):\s*//; $who = $1; for $field ( split )
{ ($key, $value) = split /=/, $field; $HoH{$who}{$key} = $value; } # reading
from file; more temps while ( <> ) { next unless s/^(.*?):\s*//; $who =
$1; $rec = {}; $HoH{$who} = $rec; for $field ( split ) { ($key, $value) = split
/=/, $field; $rec->{$key} = $value; } } # calling a function that returns a
key,value hash for $group ( "simpsons", "jetsons",
"flintstones" ) { $HoH{$group} = { get_family($group) }; } # likewise,
but using temps for $group ( "simpsons", "jetsons",
"flintstones" ) { %members = get_family($group); $HoH{$group} = {
%members }; } # append new members to an existing family %new_folks = (
"wife" => "wilma", "pet" =>
"dino"; ); for $what (keys %new_folks) { $HoH{flintstones}{$what} =
$new_folks{$what}; }
# one element $HoH{flintstones}{wife} = "wilma"; # another element
$HoH{simpsons}{lead} =~ s/(\w)/\u$1/; # print the whole thing foreach $family (
keys %HoH ) { print "$family: { "; for $role ( keys %{ $HoH{$family} }
) { print "$role=$HoH{$family}{$role} "; } print "}\n"; } #
print the whole thing somewhat sorted foreach $family ( sort keys %HoH ) { print
"$family: { "; for $role ( sort keys %{ $HoH{$family} } ) { print
"$role=$HoH{$family}{$role} "; } print "}\n"; } # print the
whole thing sorted by number of members foreach $family ( sort { keys
%{$HoH{$b}} <=> keys %{$HoH{$b}} } keys %HoH ) { print "$family: {
"; for $role ( sort keys %{ $HoH{$family} } ) { print
"$role=$HoH{$family}{$role} "; } print "}\n"; } # establish
a sort order (rank) for each role $i = 0; for ( qw(lead wife son daughter pal
pet) ) { $rank{$_} = ++$i } # now print the whole thing sorted by number of
members foreach $family ( sort { keys %{$HoH{$b}} <=> keys %{$HoH{$b}} }
keys %HoH ) { print "$family: { "; # and print these according to rank
order for $role ( sort { $rank{$a} <=> $rank{$b} keys %{ $HoH{$family} } }
) { print "$role=$HoH{$family}{$role} "; } print "}\n"; }
Here's a sample showing how to create and use a record whose fields are of many
different sorts:
$rec = { TEXT => $string, SEQUENCE => [ @old_values ], LOOKUP => {
%some_table }, THATCODE => \&some_function, THISCODE => sub { $_[0] **
$_[1] }, HANDLE => \*STDOUT, }; print $rec->{TEXT}; print
$rec->{LIST}[0]; $last = pop @ { $rec->{SEQUENCE} }; print
$rec->{LOOKUP}{"key"}; ($first_k, $first_v) = each %{
$rec->{LOOKUP} }; $answer = &{ $rec->{THATCODE} }($arg); $answer =
&{ $rec->{THISCODE} }($arg1, $arg2); # careful of extra block braces on
fh ref print { $rec->{HANDLE} } "a string\n"; use FileHandle;
$rec->{HANDLE}->autoflush(1); $rec->{HANDLE}->print(" a
string\n");
%TV = ( "flintstones" => { series => "flintstones",
nights => [ qw(monday thursday friday) ], members => [ { name =>
"fred", role => "lead", age => 36, }, { name =>
"wilma", role => "wife", age => 31, }, { name =>
"pebbles", role => "kid", age => 4, }, ], },
"jetsons" => { series => "jetsons", nights => [
qw(wednesday saturday) ], members => [ { name => "george", role
=> "lead", age => 41, }, { name => "jane", role
=> "wife", age => 39, }, { name => "elroy", role
=> "kid", age => 9, }, ], }, "simpsons" => { series
=> "simpsons", nights => [ qw(monday) ], members => [ { name
=> "homer", role => "lead", age => 34, }, { name
=> "marge", role => "wife", age => 37, }, { name
=> "bart", role => "kid", age => 11, }, ], }, );
# reading from file # this is most easily done by having the file itself be # in
the raw data format as shown above. perl is happy # to parse complex
datastructures if declared as data, so # sometimes it's easiest to do that #
here's a piece by piece build up $rec = {}; $rec->{series} =
"flintstones"; $rec->{nights} = [ find_days() ]; @members = (); #
assume this file in field=value syntax while (<>) { %fields = split
/[\s=]+/; push @members, { %fields }; } $rec->{members} = [ @members ]; # now
remember the whole thing $TV{ $rec->{series} } = $rec;
########################################################### # now, you might
want to make interesting extra fields that # include pointers back into the same
data structure so if # change one piece, it changes everywhere, like for
examples # if you wanted a {kids} field that was an array reference # to a list
of the kids' records without having duplicate # records and thus update
problems. ########################################################### foreach
$family (keys %TV) { $rec = $TV{$family}; # temp pointer @kids = (); for $person
( @{$rec->{members}} ) { if ($person->{role} =~ /kid|son|daughter/) { push
@kids, $person; } } # REMEMBER: $rec and $TV{$family} point to same data!!
$rec->{kids} = [ @kids ]; } # you copied the list, but the list itself
contains pointers # to uncopied objects. this means that if you make bart get #
older via $TV{simpsons}{kids}[0]{age}++; # then this would also change in print
$TV{simpsons}{members}[2]{age}; # because $TV{simpsons}{kids}[0] and
$TV{simpsons}{members}[2] # both point to the same underlying anonymous hash
table # print the whole thing foreach $family ( keys %TV ) { print "the
$family"; print " is on during @{ $TV{$family}{nights} }\n";
print "its members are:\n"; for $who ( @{ $TV{$family}{members} } ) {
print " $who->{name} ($who->{role}), age $who->{age}\n"; }
print "it turns out that $TV{$family}{'lead'} has "; print scalar ( @{
$TV{$family}{kids} } ), " kids named "; print join (", ",
map { $_->{name} } @{ $TV{$family}{kids} } ); print "\n"; }
You cannot easily tie a multilevel data structure (such as a hash of hashes) to
a dbm file. The first problem is that all but GDBM and Berkeley DB have size
limitations, but beyond that, you also have problems with how references are to
be represented on disk. One experimental module that does attempt to partially
address this need is the MLDBM module. Check your nearest CPAN site as described
in the perlmod manpage for source code to MLDBM.
perlref(1), perllol(1), perldata(1), perlobj(1)
Tom Christiansen <tchrist@perl.com>
Last update: Mon Jul 8 05:22:49 MDT 1996